Craps

Dice Control Martingale

Spread the love


For random players a Martingale is a dangerous way to bet. Doubling and doubling thinking that you finally must win can devastate a player when he reaches the table limit in seven or eight decisions.

But what about a controlled shooter? Say he played the field and after each loss double his bet? Would a controlled shooter be able to beat the casino by using such a Martingale?

Just wondering.

Have any of you played this way?


Replies:

Posted by: Dr Crapology on August 23, 2012, 1:49 pm

Haven’t played a Martingale with a field bet.

Just a thought—why vary from the GTC philosoply of Pass Line with odd, Come Bet with odds, and place the 6 and 8 which have a house vig of less than 1%? The field bet has a much higher house big.

Doc

Posted by: Stephen C on August 23, 2012, 1:51 pm

Using your proposition with a $5 Pass line bet, no odds, I would be busted after 6 attempts with the dice. Were you to win at the $40 dollar level you would make a profit, yes your a Winner of $5 dollars. Hell it doesn’t matter where the win comes, you only get that same lousey $5 bucks. Lose $315 total or win keeping your $160 that’s on the table and get paid an addittional $160. Take that $320, make yourself "Whole" and walk away with $5 bucks. Hardly worth the effort wouldn’t you say.

Flat bet, no odds
5, 10 (15), 20 (35), 40 (75), 80 (155), 160 (315)

I cringe to think about the complications brought to this scenario were we to add odds or Place/Come bets. However, I believe the Return on Investment regardless of where the win occurs would not justify the risk of loss.

No for an Advantage Player the Martingale is not a proper method of play. Actually, it’s not ever a good way to play/bet for anyone.

Posted by: Guest on August 23, 2012, 1:59 pm

With a Martingale you start betting low(because of the eventual table limit). $5, $10, $20, $40, $80, $160, $320, $640, $1280…

If you win you get back all of your losses and you win only $5 while you have exposed yourself to large losses!

Most players can’t start betting $25, $50, $100, $200, $400, $800, $1600, $3200… to win only $25.

Posted by: Guest on August 23, 2012, 2:12 pm

[list=disc]Next try a Fibonacci numbers sequence:

The Fibonacci numbers are the numbers in the following integer sequence:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144,…[/list]
It isn’t much better, but you make a bigger profit when you eventually hit.

==========================================================

Mathematics :
The unending sequence 1, 1, 2, 3, 5, 8, 13, 21, 34, … where each term is defined as the sum of its two predecessors.

Posted by: fscobe on August 23, 2012, 3:30 pm

A dice control Martingale on the Pass Line would be somewhat unusual. Odds are usually not specified in the minimum to maximum bets posted on the table. If you have a 10X odds game with a maximum bet of $1,000 you can put $1,000 on the Pass Line and $10,000 in odds.

With that let us say the table is $10 with a maximum of $1,000 and 10X odds. So your first bet is $5 and you lose. The next bet would also be $5. If it won, you are even.

Now what if that second bet goes to a number? You take $5 or $6 (on the 5 or 9) in odds. A win brings you back to even on the Pass Line but also gives you a win on the odds. Now you are ahead. If you lose, you have lost the $5 and the odds and you have to wait for your next turn with the dice. How would you bet that turn?

So your Martingale would have to consider the odds bet too. This can get complicated but you can see it would take a big, bad sequence for you to lose enough to hit table max — as long as you are the shooter that is.

Maybe someone would like to figure this out so we can see how long it would take to hit the table max of $1,000 on the Pass Line with $10,000 in odds? You start at $5, using odds when the point is established.

Interesting proposition.