I know it is considered a bad strategy but it seems to me that it makes a lot of sense. If you lose you double up your bet and when you finally win you get back all your losses and your initial win. I know the house has a maximum on what you can bet but seriosly how many times have you ever lost enough decisions to hit a full Martindale loss? It is a strategy that makes sense to me.
Replies:
Posted by: Skinny on July 27, 2012, 3:24 pm
Posted by: Guest on July 27, 2012, 3:32 pm
Negative Progressions: ie. Martingale system
"With a negative progression system has you increase your bets after a loss. in hopes of getting back to even after a win."
The Martingale system is a disaster waiting to happen.
Positive Progressions: ie. Paroli Betting System
"The Positive Progressions betting strategy is to bet more when you are winning and less when you are losing."
You never know when a streak occurs until it ends.
—————————————————————————-
You might consider:
[list]Captain’s Three Strong Points
[*]Use the Five Count[/*]
[*]Make Sensible Bets[/*]
[*]Develop a Controlled Throw[/*][/list]
Posted by: Agame on July 27, 2012, 3:49 pm
Keep records of your numbers for a certain amount of time, then do a betting simulation to determine if you would have won using that system in light of the numbers that were thrown. Might be a fun exercise. I am not even sure what the heck a Martindale is exactly, as I use the bread-and-butter play method.
But if you’re a controlled shooter and have different than random results, do go and see for yourself if it’s worth it.
Posted by: Guest on July 27, 2012, 4:45 pm
Agame said: I am not even sure what the heck a Martindale is exactly
[list]Double your bet is a simple Martingale:
[*]You bet $5 and you lose.[/*]
[*]You bet $10. If you lose:[/*]
[*]You bet $20. If you lose:[/*]
[*]You bet $40. If you lose:[/*]
[*]You bet $80. If you lose:[/*]
[*]You bets $160. If you lose:[/*]
[*]You bet $320. If you lose:[/*]
[*]You bet $640, which exceeds the maximum bet for many tables.[/*][/list]
If you win you get back all of your losses and you win only $5 while you have exposed yourself to large losses!
Posted by: Finisher on July 27, 2012, 5:02 pm
Good Rolling. 😀
Posted by: Agame on July 27, 2012, 8:25 pm
Thanks for the correction and explanation of the system.
I’m sweating just thinking of risking over $600 all at once to merely recover any losses 😐 . That’s a tough system if luck or skill decide not to show up.
I challenge you to the following, though:
In practice, bet the field and use the Martingale. Set for craps and field numbers. Give yourself a $500 bankroll. Report back on what happened to it after 36 rolls of the dice.
I can’t do it today myself but I’ll post tomorrow; I bet I can beat ya and make more funny money!! 😛
Anyone else wanna join the challenge?
Posted by: Guest on July 27, 2012, 8:32 pm
I’ll take the challenge, but I’ll use the Hardway Set and miss toss it by not landing the dice flat(twist of the wrist).
Good for Horn Numbers and Field Bet Numbers.
Posted by: Guest on July 27, 2012, 10:43 pm
If you wish to play a Martingale there, let me know. I like to watch.
I’ve seen the dice go around the table without anyone making a point(10 players).

Posted by: Guest on July 27, 2012, 11:22 pm
You can right click on the spreadsheet to View and enlarge it.

Posted by: Skinny on July 28, 2012, 12:05 am
With a $1,300 bankroll you would need 8 PL losses in a row to go bust. There is a 0.437067% chance of having 8 successive PL losses. That would be a little less than 1/2 of one percent. But you need to have the guts to bet $640 on the eighth try to win $5 if it should come to that. If you did happen to lose 8 in a row, you would have a loss of $1,275.
So as I said before, it is a fantastic strategy until it loses 🙂
Posted by: Finisher on July 28, 2012, 6:59 am
So is there any math that says out of 100 rollers there will be – number that will make one point on average ?
Good Rolling. 😀
Posted by: Skinny on July 28, 2012, 2:38 pm
"Finisher" wrote: Skinny You just reinforced why I should not bet the pass line on cf ers.
So is there any math that says out of 100 rollers there will be – number that will make one point on average ?
Good Rolling. 😀
If you are saying you are not going to bet on cf ers at all that is a good thing. But if you are saying you are going to make a different wager on cf ers, then that is a bad idea. Pass/Come or Don’t Pass/Don’t Come are the best wagers you can make on a random roller. You will lose money betting on cf ers in the long run. But you will lose less and lose it slower if you only bet the Pass/Come or Don’t Pass/Don’t Come instead of any other wager on them.
I don’t know why you are asking about how many rollers make a point? A line bet can be resolved without establishing a point number. You win or lose your wager if the shooter rolls a 2/3/7/11 or 12 just as easily as if the shooter makes or does not make a point number.
So here are the possible outcomes of the pass/come bet and their associated probabilities:
Player wins on come out roll: 22.22%
Player loses on come out roll: 11.11%
Player wins on a point: 27.07%
Player loses on a point: 39.60%
That can be translated to somewhat answer the question you asked. Once a player establishes a point he will make the point 40.60% of the time.
Posted by: Guest on July 28, 2012, 6:15 pm
That is only approximately 2/3 of the time!!!
Remember that is for the average random shooter, as for me well… ???
Posted by: Finisher on July 29, 2012, 4:44 am
"Skinny" wrote: In a random game you are better off betting the pass line instead of the field because it has a lower house advantage and therefore a better chance of winning. To take a realistic look at a martingale on a pass line wager we start with the 50.707% chance that the wager loses.
With a $1,300 bankroll you would need 8 PL losses in a row to go bust. There is a 0.437067% chance of having 8 successive PL losses. That would be a little less than 1/2 of one percent. But you need to have the guts to bet $640 on the eighth try to win $5 if it should come to that. If you did happen to lose 8 in a row, you would have a loss of $1,275.
So as I said before, it is a fantastic strategy until it loses 🙂
So is it 50.707 or 22.2 ?
I am a little confused .
I don’t like the martindale idea but was wondering about it if you did it on the pass line only. What would the likely hood of the roll going 8 or more rollers with out one making a point.
I one time bet the 8 and it took 4 rollers and 42 numbers till I hit it. If I was using this strategy I think I would have given up sooner.
How often is a point made ?
Good Rolling. 😀
Posted by: Skinny on July 29, 2012, 6:15 am
He can win the pass line wager on the come out roll with a 7/11 or by establishing and making his point.
He can lose the pass line wager on the come out roll with a 2/3/12 or be establishing and not making his point.
You can not just look at the number of players who make their point. Players can win or lose the pass line wager on the come out roll as well.
A player will win his pass line wager with a 7 or 11 approximately 22.22% of the time.
A player will win his pass line wager by making his point 27.07% of the time.
Adding up the ways a player can win his pass line wager gives 22.22% + 27.07% = 49.29% of the time that a player will win his pass line wager.
A player will lose his pass line wager with a 2, 3 or 12 approximately 11.11% of the time.
A player will lose his pass line wager by NOT making his point 39.60% of the time.
Adding up the ways a player can lose his pass line wager gives 11.11% + 39.60% = 50.71% of the time that a player will lose his pass line wager.
If you do the martingale on the pass line you have to consider rolling a 7 or 11 on the come out roll in addition to making the point.